To rewrite the left side of the equation \(2(4x + 5)\) without parentheses, you can distribute the 2:
\[ 2(4x + 5) = 2 \cdot 4x + 2 \cdot 5 \]
Calculating each term gives:
\[ 2 \cdot 4x = 8x \quad \text{and} \quad 2 \cdot 5 = 10 \]
So, we have:
\[ 2(4x + 5) = 8x + 10 \]
Now, we can equate \(8x + 10\) to \(10x + 2\):
\[ 8x + 10 = 10x + 2 \]
This implies that:
\[ ? + ? = 10x + 2 \quad \text{is} \quad 8x + 10 \]
Thus, you can write:
\[ 8x + 10 = 10x + 2 \]
So, we can say that:
\[ 8x + 10 , \text{corresponds to} , ? + ? = 10x + 2. \]
In summary, you have \(8x\) and \(10\) as the components.