Water, with a density of ρ=1180 kg/m3, flows in a horizontal pipe. In one segment of the pipe, the flow speed is v1=7.73 m/s. In a second segment, the flow speed is v2=3.77 m/s. What is the difference between the pressure in the second segment (P2) and the pressure in the first segment (P1)?

Answer 1

P1-P2=1/2 *1180*(V2^2-v1)^2
differance in pressure=590(3.77^2-7.73^2) pascal