Water, with a density of p=1135 kg/m^3, flows in a horizontal pipe. In one segment of the pipe, the flow speed is v1=6.73 m/s. In a second segment, the flow speed is v2= 2.37 m/s. What is the difference between the pressure P2 in the second segment an the pressure P1 in the first segment?

Answer 1

To find the difference in pressure between the two segments, we can use Bernoulli's equation:

P1 + 1/2 ρv1^2 = P2 + 1/2 ρv2^2

Where:
P1 = pressure in the first segment
P2 = pressure in the second segment
ρ = density of water = 1135 kg/m^3
v1 = flow speed in first segment = 6.73 m/s
v2 = flow speed in second segment = 2.37 m/s

Now we can plug in the values and solve for the pressure difference:

P1 + 1/2 * 1135 * 6.73^2 = P2 + 1/2 * 1135 * 2.37^2

P1 + 70962.305 = P2 + 14959.755

P1 - P2 = 70962.305 - 14959.755
P1 - P2 = 56002.55

Therefore, the pressure difference between the two segments is 56002.55 Pa.