Please label the School Subject. Science?
Sra
Water left at 150 degrees to cool in 80 degree rm. After t min temp of water is given by t(t)=80+70e^-0.096t
Find temp 10 min later
2 answers
Just substitute 10 for t (minutes) and perform the indicated calculation.
T(10 min) = 80 + 70 e^-0.96 = 80 + 26.8
= 106.8 F
(I am assuing Fahrenheit temperatures, since I cannot imagine an 80 C room, or liquid water at 150 C.)
T(10 min) = 80 + 70 e^-0.96 = 80 + 26.8
= 106.8 F
(I am assuing Fahrenheit temperatures, since I cannot imagine an 80 C room, or liquid water at 150 C.)
1 answer