You say the small tanks drains at a rate of ? ft^3/s
so for the large tank,
dv/dt = ?
I expect you may want to proofread your post and update it a bit.
Water is draining from a small cylindrical tank into a larger one below it. The small cylindrical tank has a radius of 4 feet and a height of 6 feet; the large cylindrical tank has a radius of 8 feet and a height of 16 feet. The small tank is initially full of water, and the water drains out at a rate of cubic feet per second.
- Let z be the depth of the water in the large tank, which is initially empty. Compute dz/dt
2 answers
1/2 ft^3/s