Water from a garden hose that is pointed 29° above the horizontal lands directly on a sunbather lying on the ground 4.7 m away in the horizontal direction. If the hose is held 1.4 m above the ground, at what speed does the water leave the nozzle?

Answer 1

Write vertical and horizontal equations of motion, with the time of flight t and the initial velocity V as the two unknowns. Solve the two equations in two unknowns.
V*cos 29*t = 0.8746 V * t = 4.7
V*sin 29*t - (g/2) t^2 =
= 0.4848 V - 0.49 t^2 = -1.4
Substitute 0.5374/V for t in the second equation, and you will end up with a single equation for V that you must solve.