Water flows steadily along a horizontal pipe at a volume rate of 8×10^-³ m³s.If the area of cross-section of the pipe is 20 cm/Calculate the velocity of the fluid?

Answer 1

To calculate the velocity of the fluid, we can use the equation:

Q = A * V

Where:
Q is the volume rate of flow (8×10^-³ m³/s)
A is the cross-sectional area of the pipe (20 cm²)
V is the velocity of the fluid that we need to determine.

First, let's convert the cross-sectional area from cm² to m²:
1 cm² = 0.0001 m²
20 cm² = 20 * 0.0001 m²
20 cm² = 0.002 m²

Now we can rearrange the equation to solve for V:
V = Q / A

Plugging in the values:
V = (8×10^-³ m³/s) / (0.002 m²)

Simplifying:
V = 4 m/s

Therefore, the velocity of the fluid is 4 m/s.