rate = 27 km/hr
= 2700000 cm / 60 minutes
= 45000 cm/min
so in 1 minute, the water flows 45000 cm
volume = area of base x height
= 5.4 cm^2 x 45000 cm
= 243000 cm^3
The area of cross section of a pipe is 5.4 centimetres square and the water pump out of it at the rate of 27 kilometre per hour find the volume of water which flows out of the pipe in 1 minute
8 answers
243
As rate= 27km/h
So when we change it into cm it becomes =2700000cm/60mins
= 45000cm/min
So in 1minute 45000cm water is pumped
As the area of base is 5.4cm^2
So volume=area of base × height
5.4×45000
=243000cm^3
Hence,the volume of water pumped in one minute is 243000cm^3.
So when we change it into cm it becomes =2700000cm/60mins
= 45000cm/min
So in 1minute 45000cm water is pumped
As the area of base is 5.4cm^2
So volume=area of base × height
5.4×45000
=243000cm^3
Hence,the volume of water pumped in one minute is 243000cm^3.
243 litres
243 litres
Explain again plz
No answer is not correct.
Area of cross section of pipe = 5.4 cm²
Velocity of water = 27km/h
= 27000m/60min
= 2700000cm/60min
= 45000cm/min
Water thrown out of pipe = Volume of water = 5.4cm² × 45000cm/min
= 243000cm³/min
Since, 1cm³=1ml
Therefore, 243000³=243000ml
=243000/1000 L
=243L
Velocity of water = 27km/h
= 27000m/60min
= 2700000cm/60min
= 45000cm/min
Water thrown out of pipe = Volume of water = 5.4cm² × 45000cm/min
= 243000cm³/min
Since, 1cm³=1ml
Therefore, 243000³=243000ml
=243000/1000 L
=243L
0 answers