The first sentence just tells you that the roundtrip is 4(2.5) or 10 km, so each way is 5 km
let his rate of rowing in still waters be x km/h
let the rate of the current be x km/h
time to go with the current = 5/(x+y) = 1
or x+y = 5
time to go against the current = 5/(x-y) = 2/3
or 2x-2y = 15
There are your two equations.
You said you knew how to solve them, let me know what you got
Walking at 4km/h, Bruce can make the roundtrip between his campsite and Lookout Point in 2.5 h. Rowing on Crooked River, he can row upstream from the campsite to Lookout Point in 1 h and can row back again in 40 min. Find Bruce’s rate of rowing in still water and the speed of the current in Crooked River.........I know how to solve i would really apreciate it if someone can give me the 2 equations.
5 answers
rate of rowing= 6.25
i don't think my solution is correct though...
i don't think my solution is correct though...
Sorry, I had my equations backwards.
Clearly the time has to be less for a faster speed
so 5/(x+y) = 2/3 --->2x+2y = 15
and 5/(x-y) = 1 ----> x-y= 5
You still get x = 6.25, but y is now 1.25
whereas before it would have been negative.
Good for you to doubt the result.
Clearly the time has to be less for a faster speed
so 5/(x+y) = 2/3 --->2x+2y = 15
and 5/(x-y) = 1 ----> x-y= 5
You still get x = 6.25, but y is now 1.25
whereas before it would have been negative.
Good for you to doubt the result.
Thank You So MUCH!!!
why did you do 2x and 2y?
1 answer