Asked by Sue
Walking at 4km/h, Bruce can make the roundtrip between his campsite and Lookout Point in 2.5 h. Rowing on Crooked River, he can row upstream from the campsite to Lookout Point in 1 h and can row back again in 40 min. Find Bruce’s rate of rowing in still water and the speed of the current in Crooked River.
Answers
Answered by
Henry
t(avg) = (40 + 60) / 2 = 50min = Time required to row the distance in still water.
V = d / t = 5km / 50min = 0.1km/min = = 6km/h in still water.
V = Vmax - Vmin,
V=5km/(2/3)h -5km / 1h=7.5 -5=2.5km/h = speed of stream.
V = d / t = 5km / 50min = 0.1km/min = = 6km/h in still water.
V = Vmax - Vmin,
V=5km/(2/3)h -5km / 1h=7.5 -5=2.5km/h = speed of stream.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.