I see very simple factors here
(w-8)(w+5) = 0
take it from here
w^2-3w-40=0 how are you supposed to solve this and how do you find the solution for w
5 answers
what about the 3w though? where does that go and how do you figure to get the numbers on the oposite side, sorry I just don't understand math
(w-8)(w+5)
using the distributive property of multipication this is
w(w+5) -8(w+5)
= w^2 + 5 w - 8 w - 40
see , you have +5w-8w = -3w
using the distributive property of multipication this is
w(w+5) -8(w+5)
= w^2 + 5 w - 8 w - 40
see , you have +5w-8w = -3w
Now, we want to know when
(w-8)(w+5) is zero
well that is if w = 8
or if w = -5
(w-8)(w+5) is zero
well that is if w = 8
or if w = -5
GIVEN: W^2 - 3W -40 = 0
Factor the equation into 2 binomials:
( W + 5 ) ( W - 8 ) = 0.
To check the factored equation,
multiply W in the first parenthesis by
each term in the 2nd parenthesis.Then,
multiply 5 in the first parenthesis by
each term in the 2nd parenthesis:
W^2 - 8W + 5W - 40 = 0.
Combine like-terms:
W^2 - 3W - 40 = 0. Checked OK.
Return to factored equation:
( W + 5 ) ( W - 8 ) = 0.
Solve for W.
If w + 5 = 0, W = - 5; If W - 8 = 0,
W = 8.
Solutions: W = -5 and W = 8.
A 2nd degree (W^2) equation has a
maximum of 2 solutions.
Factor the equation into 2 binomials:
( W + 5 ) ( W - 8 ) = 0.
To check the factored equation,
multiply W in the first parenthesis by
each term in the 2nd parenthesis.Then,
multiply 5 in the first parenthesis by
each term in the 2nd parenthesis:
W^2 - 8W + 5W - 40 = 0.
Combine like-terms:
W^2 - 3W - 40 = 0. Checked OK.
Return to factored equation:
( W + 5 ) ( W - 8 ) = 0.
Solve for W.
If w + 5 = 0, W = - 5; If W - 8 = 0,
W = 8.
Solutions: W = -5 and W = 8.
A 2nd degree (W^2) equation has a
maximum of 2 solutions.
2 answers