Rewrite it as
(tanx + coty)/(tanx coty) = tany + cotx
LS = (sinx/cox + cosy/siny)/((sinx/cosx)(cosy/siny))
= [(sinxsiny + cosxcosy)/(cosxsiny) ] / [(sinxcosy)/(cosxsiny) ]
= (sinxsiny + cosxcosy)/(sinxcoy) (after multiplying by the reciprocal)
= sinxsiny/(sinxcosy) + cosycosx/)sinxcosy)
=siny/cosy + cosx/sinx
= tany + cotx
= RS
Verify the identity algebraically.
TAN X + COT Y/TAN X COT Y= TAN Y + COT X
1 answer
1 answer