Velocity and Acceleration Quick Check

Question

4 of 54 of 5 Items

Question
Use the equation for motion to answer the question.

x=x0+v0t+12at2
An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?

(1 point)
Responses

30 m
30 m

60 m
60 m

17 m
17 m

32 m

Answer 1

To find the final position of the object after 1s, we can use the equation for motion given:

x = x0 + v0t + 1/2at^2

Given:
x0 = 2 m (starting position)
v0 = 15 m/s (starting velocity)
t = 1 s

Substituting these values into the equation:

x = 2 + 15(1) + 1/2(0)(1)^2
x = 2 + 15 + 0
x = 17 m

Therefore, the final position of the object after 1s is 17 m.