To determine the final position of the object after 1 second, we can use the motion equation provided:
\[ x = x_0 + v_0t + \frac{1}{2}at^2 \]
Given:
- Starting position (\( x_0 \)) = 2 m
- Starting velocity (\( v_0 \)) = 15 m/s
- Time (\( t \)) = 1 s
- Acceleration (\( a \)) = 0 m/s² (constant speed means no acceleration)
Substituting the given values into the equation:
\[ x = 2 , m + (15 , m/s)(1 , s) + \frac{1}{2}(0 , m/s^2)(1 , s)^2 \]
This simplifies to:
\[ x = 2 , m + 15 , m + 0 \]
\[ x = 17 , m \]
Therefore, the final position of the object after 1 second is 17 m.