Question
(Velocity and acceleration.) The acceleration of gravity on the surface of the Moon is a = 1.6 m/s2, as opposed to g = 9.8 m/s2 on Earth. An Olympic high-jumper can jump to about 2.35 m on the surface of the Earth. What height could an Olympic high-jumper reach on the surface of the Moon?
Answers
Damon
m g h = (1/2) m v^2
h = v^2/2g
v the same
v^2 = 2 g h
2 * 9 .8 * 2.35 = 2 * 1.6 * h
h = 14.4 meters
h = v^2/2g
v the same
v^2 = 2 g h
2 * 9 .8 * 2.35 = 2 * 1.6 * h
h = 14.4 meters