Question

(Velocity and acceleration.) The acceleration of gravity on the surface of the Moon is a = 1.6 m/s2, as opposed to g = 9.8 m/s2 on Earth. An Olympic high-jumper can jump to about 2.35 m on the surface of the Earth. What height could an Olympic high-jumper reach on the surface of the Moon?

Answer 1

m g h = (1/2) m v^2
h = v^2/2g

v the same
v^2 = 2 g h

2 * 9 .8 * 2.35 = 2 * 1.6 * h

h = 14.4 meters