uu) lim ln(1-x) as x->1-

Question

yy) lim (√(6-x)-2)/(√(3-x)-1) as x-> 2

zz) lim (1-(1/2)arctanx) as x->-∞

bbb) lim ln|1-x| as x->1

If these are hard to interpret with all the parentheses, you can plug them in to Wolfram Alpha and it interprets them perfectly.

Answer 1

Sorry, I forgot one:

w) lim (1-2cos^2x)/(cosx-sinx) as x->π/4

Answer 2

if you've already been to wolfram, and it shows steps as needed, why bother posting here?