I tried doing some conversion factors and came up with this:
(0.101g Mg)(1mol MgO) |(40.31g MgO)
----------------------
(24.31g Mg)|(1mol MgO)
=~0.167g MgO as my theoretical yield if I had a mass of 0.101g of Mg
Did I do this correctly?
Using your mass of Mg (0.101g), and assuming all of the Mg burns in oxygen and forms the theoretical predicted product, calculate the theoretical yield of magnesium oxide.
I wrote out the equation and it turned out to be:
2Mg+O2->2MgO
I have my mass of Mg but how do I get to the theoretical yield of how much MgO is formed? Thanks in advance!
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