A. 4 * 2^3 over 2^3
B. 2 * 2^3 over 2^4
C. 3 * 2^3 over 2^4
D. 3 * 2^4 over 2^4
Using the numbers 3, 2, and 4, which of these problems would have a solution of 4?
A. 4 • start fraction 2 superscript 3 baseline over 2 superscript 3 baseline end fraction
B. 2 • start fraction 2 superscript 3 baseline over 2 superscript 4 baseline end fraction
C. 3 • start fraction 2 superscript 3 baseline over 2 superscript 4 baseline end fraction
D. 3 • start fraction 2 superscript 4 baseline over 2 superscript 4 baseline end fraction
11 answers
something divided by itself equals one
something multiplied by one equals itself
something multiplied by one equals itself
what is the answer
What’s the answer mine only gives me one choice
1. -9
2.y^19
3.w^-6
4.2^3/2^3
5.taylor changed the negative exponent to a negative base. the problem should be 2^-4 = 1/2^4= 1/2.2.2.2=1/16
2.y^19
3.w^-6
4.2^3/2^3
5.taylor changed the negative exponent to a negative base. the problem should be 2^-4 = 1/2^4= 1/2.2.2.2=1/16
Guys answers ;) is correct!! I got 100
thank youuuuuu:)
answers is correct!! thank you <33
Answer is correct!
Thank god i havent found any answers for math since eighth grade started i was worried
also tysm answers <3
1 answer