I don't agree. If you are solving this problem by comparing the Ksp values, that's the wrong way to do it. You must actually calculate the solubility BECAUSE
a and b are sqrt Ksp while c and d are (Ksp/4)^1/3. Without going through any of the calculations I suspect b is correct because surely PbS is the smallest and a is the only answer that begins with PbS. I could be wrong but you should confirm that by actually calculating each then you can arrange them from low to high.
Using the information below, which answer lists the salts in order of increasing solubility?
PbSO4 Ksp = 1.6 x 10^-8
PbS Ksp = 8 x 10^-28
PbI2 Ksp = 7.1 x 10^-9
PbCl2 Ksp = 1.6 x 10^-5
a. PbS < PbI2 < PbSO4 < PbCl2
b. PbI2 < PbCl2 < PbS < PbSO4
c. PbCl2 < PbI2 < PbSO4 < PbS
I believe the answer is B.
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