The equation you gave is a straight line.
There is no such thing as a tangent to a straight line, since that would have to be the line itself.
Since the point given is not on your given line, I suspect a typo
did you mean
y = 2x^(-1/2) ?
Using the definition of the derivative, find the equation of the tangent line to y=2x-1/2 at (1/2,-1)
Thanks!!
1 answer