Using heat exchange and conservation of thermal energy, determine the specific heat capacity for your metal.

Question

So the data we have is:
Aluminium:
Mass - 0.004
Initial temp - 100C
Final temp: 32C

Water:
Mass -0.1
Initial temp - 20C
Final temp - 32C

I know that the formula is mct = mct but I don't get what I'm solving for or how to do it.

Thank you for your help!

Answer 1

assuming kilograms (please specify units)

water is 4180 J/(kg deg C)
heat into water = (0.1)4180*(32-20)

Al is C J/(kg deg C)
heat out od Al = .004(C)(100-32)
so
.004(C)(100-32)=(0.1)4180*(32-20)

Answer 2

Thank you for answering! So when I did the math I got 18,441 j/kg degree c

However the actual value is supposed to be 900.did I do the math wrong or did I just do something wrong in the experiment? Thanks!