I am sure you wanted y'
8x - 18y dy/dx = 0
-18y dy/dx = -8x
dy/dx = 8x/(18y) = 4x/(9y)
-9y^2 = 36 - 4x^2
y^2 = (4x^2 - 36)/9
y = (4x^2 - 36)^(1/2) /3
dy/dx = (1/6) (4x^2 - 36)^(-1/2) (8x)
= (4/3)(x)(4x^2 - 36)^(-1/2)
Using 4x^2 - 9y^2 = 36
Find y by implicit differentiation and then solve the equation explicitly for y and differentiate to get y' in terms of x.
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