Use trig identities to transform the expression (sec θ)/(csc θ) into a single trig function. Assume θ is acute. Work must be shown for credit.

1 answer

(sec θ)/(csc θ)
= (1/cos θ)(1/sin θ) , but we know sin 2A = 2sinAcosA
= 1/(sinθcosθ)
= 2/sin(2θ)