construct your right-angled triangle.
r^2 = x^2 + y^2 , (x is a side , not an angle)
2^2 = x^2 + 1^2 , since sinØ = opposite/hypoenuse or y/r
x^2 = 3
x = √3 , we know the angle must be in Quad I
sinx = 1/2 --- given
cscx = 2
cosx = √3/2
secx = 2/√3
tanx = 1/√3
cotx = √3
by the way, you angle x would be π/6 or 30°
Use the value sin x = 1/ 2 and cos x > 0 to find the values of all six trigonometric functions.
Leave your answer in exact form, not in decimal
1 answer
1 answer