To find the missing values \( x \) and \( y \) in the table, we need to analyze the ratios presented.
The ratios presented can be established as follows:
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For \( 8 \) and \( 48 \): \[ \frac{48}{8} = 6 \]
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For \( 10 \) and \( 60 \): \[ \frac{60}{10} = 6 \]
From the above analysis, both ratios give us a constant multiplier of \( 6 \). We can use this to find the missing values \( x \) and \( y \).
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To find \( x \): \[ \frac{72}{x} = 6 \ 72 = 6x \ x = \frac{72}{6} = 12 \]
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To find \( y \): \[ \frac{84}{y} = 6 \ 84 = 6y \ y = \frac{84}{6} = 14 \]
So, the missing values are \( x = 12 \) and \( y = 14 \).
The answer is: 12; 14
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