To find the missing values of \(x\) and \(y\) in the table, we can analyze the ratios. The table shows pairs of numbers formatted as:
\[ \begin{array}{c|c} \text{First value} & \text{Second value} \ \hline 8 & 48 \ 10 & 60 \ x & 72 \ y & 84 \ \end{array} \]
Let's start with the known pairs to identify a pattern:
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For the first pair (8, 48): \[ \frac{48}{8} = 6 \] This indicates that the second value is 6 times the first.
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For the second pair (10, 60): \[ \frac{60}{10} = 6 \] This shows that this ratio is also 6 times.
Now we apply this ratio to find \(x\) and \(y\).
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For \(x\) and 72: \[ 72 = 6x \implies x = \frac{72}{6} = 12 \]
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For \(y\) and 84: \[ 84 = 6y \implies y = \frac{84}{6} = 14 \]
Thus, the missing values are \(x = 12\) and \(y = 14\).
The response is: 12; 14
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