Use the table below to evaluate the derivative with respect to x of g of f of 2 times x at x = 1.

Question

x 1 2 3 4
f(x) 6 1 8 2
f ′(x) 6 1 8 2
g(x) 1 4 4 3
g ′(x) 9 5 5 –4

Answer 1

That would be

f'(g(2x))g'(2x)(2x)'
= f'(g(2))g'(2)(2)
= f'(4)g'(2)(2)
= 2*4*2
= 16