Use the substitution method to solve the system 2.5x+y=−2, 3x+2y=0

.(1 point)
Responses

(−2,3)

left parenthesis negative 2 comma 3 right parenthesis
no solution
no solution
infinite solutions
infinite solutions
(3,−2)

1 answer

To solve the system of equations using the substitution method, we'll start with the given equations:

  1. \(2.5x + y = -2\)
  2. \(3x + 2y = 0\)

Step 1: Solve one of the equations for one variable.

We'll solve the first equation for \(y\):

\[ y = -2 - 2.5x \]

Step 2: Substitute this expression for \(y\) into the second equation.

Substituting \(y\) in the second equation:

\[ 3x + 2(-2 - 2.5x) = 0 \]

Step 3: Simplify and solve for \(x\).

This simplifies to:

\[ 3x - 4 - 5x = 0 \]

Combining like terms gives:

\[ -2x - 4 = 0 \]

Solving for \(x\):

\[ -2x = 4 \implies x = -2 \]

Step 4: Substitute \(x\) back into the expression for \(y\).

Now substitute \(x = -2\) back into the equation we found for \(y\):

\[ y = -2 - 2.5(-2) \]

Calculating this gives:

\[ y = -2 + 5 = 3 \]

Step 5: Write the solution as an ordered pair.

Thus, the solution to the system of equations is:

\[ (x, y) = (-2, 3) \]

Final Answer:

The solution is \((-2, 3)\).