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Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction:

2 NO(g) + O2(g) → 2 NO2(g), ΔH°rxn = ?

Given:
N2(g) + O2(g) → 2 NO(g), ΔH°rxn = +183 kJ

1/2 N2(g) + O2(g) → NO2(g), ΔH°rxn = +33 kJ

3 answers

Reverse equation 1 (change sign of delta H).
Multiply equation 2 by 2.
Add.
Check the equation to make sure that's what you get.

133

-183+66=-117

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