Consider the following reaction:

H2(g) + I2(s) ---> 2HI(g)
TriangleH = 51.9 kj (enthalpy)

Calculate the standard enthalpies of reaction for the following reaction:

6HI(g) ---> 3H2(g) + 3I2(s)

Thanks!

1 answer

You want the reverse of 3x the rxn.
That will be -51.9*3 kJ
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