If I understand what you did, I disagree with the answer. Dividing k1 by 2 means you have the reacton 1/2 A --> 1/4 B and that won't add up to anything.
I think what you want to do is to multiply equation 1 by 2 to give you
2A ==>B + 2C
Then reverse equation 2 to give
2C + B ==> 3D
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Then add those two equations to obtain
2A ==> 3D which is what the problem asked for.
So you want to square k1 and reverse k2, then multiply those.
Check me out on that.
Use the reactions below to predict the equilibrium constant for the reaction 2A(g)<->3D(g)
A(s)<->1/2B(g)+C(g) k1=0.0334
3D(g)<->B(g)+2C(g) k2=2.35
I know that you have to make modifications according to the stoichiometric coeffecients. So do I divide k1 by 2 and the multiply that by the inverse of 2.35 (which = 1/2.35 because the equation is reversed)?
I got this answer, is this correct?
0.0034/2=0.0167*(1/2.35)
=0.0071
is this correct?
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