Try roots of the form x = +/- p/q, where p is an integer factor of 14 (1,2,7,14) and q is a factor of 4 (1,2,4)
You will have to chooose a negative value of x to get a negative or zero value of f(x). Try x = -2/1 = -2
f(x) = 64 - 72 + 120 -126 + 14 = 0
So x = 2 is a solution . You can get another real root by dividing
(4x^4+9x^3+30x^2+63x+14)/(x+2)
and solving the remaining cubic.
The third and fourth roots are complex conjugates.
use the rational zero theorem to find all the real zeros of the polynomial function. use the zeros to factor f over the real numbers:
f(x)=4x^4+9x^3+30x^2+63x+14
I cant even find sample problems to help me figure this out. help me please?
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