To find zeros, I would have tried x = ±3, and ± 2/3
for f(x)
However, this is a poor equation to use, since it doesn't have any rational factors at all.
use the rational theorem to select the values that are possible zeroes of the function f(x)=6x^3-2x^2+x+3 select all that apply
-3
-2/3
3/2
6
3 answers
the answers are -3 and 3/2
c
b
c
a and c
b
c
a and c