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Use the limit process to find the slope of the graph of sqrt(x + 8) at (8, 4).Asked by Morgan
Use the limit process to find the slope of the graph of
sqrt(x + 8) at (8, 4).
sqrt(x + 8) at (8, 4).
Answers
Answered by
Steve
Just so you can check your work, you should come up with 1/8
Answered by
bobpursley
slope= lim (sqrt(x+8+dx)-sqrt(x+8))/dx
multipy num/den by sqrt(x+8+dx)+sqrt(x+8)
slope= lim (x+8+dx-x-8)/(dx*(sqrt(x+8+dx)+sqrt(x+8)
slope= lim ((dx/dx)/sqrt(x+8+dx)+sqrt(x+8)
= 1/(2(sqrt(x+8))
so at x=8, slope= 1/8
multipy num/den by sqrt(x+8+dx)+sqrt(x+8)
slope= lim (x+8+dx-x-8)/(dx*(sqrt(x+8+dx)+sqrt(x+8)
slope= lim ((dx/dx)/sqrt(x+8+dx)+sqrt(x+8)
= 1/(2(sqrt(x+8))
so at x=8, slope= 1/8
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