use the limit process to find the area of the region between f(x) = x^2 + 2 a interval [0, 3]

Answer 1

I think all you do is integrate this from 0 to 3

So the integral of x^2 + 2:

integral of x^2:
x^3/3

integral of 2:
2x

so integral:

x^3/3 + 2x

now integrate this from 0 to 3:

from 3:
3^3/3 + 2*3 = 15

from 0:
0^2+2*0 = 0

15 - 0 = 15

I think this is how you approach this. I don't know what the limit process is, but I can't see what else you could do considering that its given you intervals to integrate at.