Use the image to answer the question.

Question

Points upper A upper C mark the ends of a line segment that slopes upward from left to right. Point upper B is at the midpoint. Identical single hash marks are between upper A and upper B and between upper B and upper C.

Nozomi constructed a copy of AB¯¯¯¯¯¯¯¯ by using point B as an endpoint of the copy of AB¯¯¯¯¯¯¯¯ and placing point C , as seen in the image. If the measure of AB¯¯¯¯¯¯¯¯ is 22.3 millimeters, what is the measure of AC¯¯¯¯¯¯¯¯ ?

(1 point)
Responses

The measure of AC¯¯¯¯¯¯¯¯ is 44.6 millimeters.
The measure of Modifying above upper A upper C with bar is 44.6 millimeters.

The measure of AC¯¯¯¯¯¯¯¯ is 66.9 millimeters.
The measure of Modifying above upper A upper C with bar is 66.9 millimeters.

The measure of AC¯¯¯¯¯¯¯¯ is 11.15 millimeters.
The measure of Modifying above upper A upper C with bar is 11.15 millimeters.

The measure of AC¯¯¯¯¯¯¯¯ is 22.3 millimeters.

Answer 1

Nozomi constructed a copy of line segment \( \overline{AB} \) from point \( B \) to point \( C \), making \( \overline{BC} \) equal in length to \( \overline{AB} \). Therefore, since the measure of \( \overline{AB} \) is 22.3 millimeters, the measure of \( \overline{BC} \) is also 22.3 millimeters.

To find the total length of \( \overline{AC} \), we can add the lengths of \( \overline{AB} \) and \( \overline{BC} \):

\[ AC = AB + BC = 22.3 \text{ mm} + 22.3 \text{ mm} = 44.6 \text{ mm} \]

Thus, the measure of \( \overline{AC} \) is 44.6 millimeters.