Use the image to answer the question.

Points upper A upper C mark the ends of a line segment that slopes upward from left to right. Point upper B is at the midpoint. Identical single hash marks are between upper A and upper B and between upper B and upper C.

Nozomi constructed a copy of AB¯¯¯¯¯¯¯¯ by using point B as an endpoint of the copy of AB¯¯¯¯¯¯¯¯ and placing point C, as seen in the image. If the measure of AB¯¯¯¯¯¯¯¯ is 22.3 millimeters, what is the measure of AC¯¯¯¯¯¯¯¯?

(1 point)
Responses

The measure of AC¯¯¯¯¯¯¯¯ is 22.3 millimeters.
The measure of Modifying above upper A upper C with bar is 22.3 millimeters.

The measure of AC¯¯¯¯¯¯¯¯ is 44.6 millimeters.
The measure of Modifying above upper A upper C with bar is 44.6 millimeters.

The measure of AC¯¯¯¯¯¯¯¯ is 11.15 millimeters.
The measure of Modifying above upper A upper C with bar is 11.15 millimeters.

The measure of AC¯¯¯¯¯¯¯¯ is 66.9 millimeters.
The measure of Modifying above upper A upper C with bar is 66.9 millimeters.
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1 answer

To determine the measure of segment \( \overline{AC} \), we note the following:

  1. The segment \( \overline{AB} \) measures 22.3 millimeters.
  2. Point \( B \) is the midpoint between points \( A \) and \( C \).

Since \( B \) is the midpoint, the entire length of segment \( \overline{AC} \) is twice the length of segment \( \overline{AB} \). Therefore, we can calculate the measure of \( \overline{AC} \) as follows:

\[ \text{Length of } \overline{AC} = 2 \times \text{Length of } \overline{AB} = 2 \times 22.3 \text{ mm} = 44.6 \text{ mm}. \]

Thus, the measure of \( \overline{AC} \) is 44.6 millimeters.

The correct response would be:

  • The measure of \( \overline{AC} \) is 44.6 millimeters.
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