Use the image to answer the question.

Long Description (if needed) The net appears as three horizontal rectangles joined one on top of another. The left, top, and bottom sides of the middle rectangle are drawn with dashed lines. The right side of the bottom rectangle is drawn with a dashed line. The width of the rectangles is 100 units. The height of the middle rectangle is 24 units. The middle rectangle has a right triangle adjoining its left side. The length of the hypotenuse of the triangle is 25 units and the length of its horizontal side at the top of the triangle is 7 units. An unmarked triangle the same size and shape as the other triangle adjoins the right side of the bottom rectangle. Its hypotenuse shares a side with the right side of the bottom rectangle.

The net of a triangular prism is shown. What is the surface area of the triangular prism?

(1 point)
Responses

5,684 square units
5,684 square units

5,668 square units
5,668 square units

5,768 square units
5,768 square units

5,936 square units
5,936 square units
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1 answer

To find the surface area of the triangular prism, we need to calculate the lateral surface area (Area of the two triangles) and the area of the three rectangles (front, back, and bottom).

The lateral surface area can be calculated as:
2 * (base of triangle * height of triangle) = 2 * (7 * 24) = 336 square units

The area of the front rectangle is:
100 * 24 = 2400 square units

The area of the back rectangle is also:
100 * 24 = 2400 square units

The area of the bottom rectangle is:
100 * 25 = 2500 square units

Now, we add these areas together to get the total surface area:
336 + 2400 + 2400 + 2500 = 7636 square units

Therefore, the surface area of the triangular prism is 7,636 square units.
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