Use the image to answer the question.

Long Description (if needed) The net appears as three horizontal rectangles joined one on top of another. The left, top, and bottom sides of the middle rectangle are drawn with dashed lines. The right side of the bottom rectangle is drawn with a dashed line. The width of the rectangles is 100 units. The height of the middle rectangle is 24 units. The middle rectangle has a right triangle adjoining its left side. The length of the hypotenuse of the triangle is 25 units and the length of its horizontal side at the top of the triangle is 7 units. An unmarked triangle the same size and shape as the other triangle adjoins the right side of the bottom rectangle. Its hypotenuse shares a side with the right side of the bottom rectangle.

The net of a triangular prism is shown. What is the surface area of the triangular prism?

(1 point)
Responses

5,936 square units
5,936 square units

5,684 square units
5,684 square units

5,668 square units
5,668 square units

5,768 square units

1 answer

To find the surface area of the triangular prism shown in the net, we need to find the areas of each individual face and then add them together.

- The area of the triangular faces can be found using the formula: 1/2 * base * height. For the large triangular faces on either side of the prism, the base is 25 units and the height is 24 units. So, the area of each of these triangular faces is 1/2 * 25 * 24 = 300 square units.

- The area of the rectangular face is simply the width times the height. The width is 100 units and the height is 24 units, so the area of this face is 100 * 24 = 2400 square units.

Now, adding up the areas of all three faces:

300 + 300 + 2400 = 3000 square units

Therefore, the surface area of the triangular prism is 3000 square units.