In a parallelogram, the diagonals bisect each other. This means that the point of intersection (point V in this case) divides each diagonal into two congruent segments.
Since segment \( ZV \) is one half of diagonal \( ZY \), its corresponding segment on the other diagonal \( WX \) would be \( WV \). Therefore, segment \( WV \) must be congruent to segment \( ZV \).
The correct response is:
WV (segment \( \overline{WV} \)).