A parallelogram has vertices upper Q, upper R, upper S, and upper T. Opposite vertices are connected via diagonal lines that intersect at an interior point labeled upper P. Sides upper Q upper R and upper T upper S are much longer than the other sides.
It is given that quadrilateral QRST is a parallelogram. Which segment of the figure must be congruent to segment SP¯¯¯¯¯¯¯?
(1 point)
Responses
QS¯¯¯¯¯¯¯
upper Q upper S
QP¯¯¯¯¯¯¯¯
upper Q upper P
PT¯¯¯¯¯¯¯
upper P upper T
PR¯¯¯¯¯¯¯¯
upper P upper R
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1 answer
In a parallelogram, the diagonals bisect each other. This means that the segments formed by the intersection of the diagonals are equal in length.
Since P is the point where the diagonals intersect, segment \( SP \) is congruent to segment \( PT \). Therefore, the correct answer is:
PT (segment \( PT \)).
1 answer
1 answer
1 answer
1 answer