Question

Use the image to answer the question.%0D%0A%0D%0A%0D%0A%0D%0AHaley is standing in the base path between second and third base when she fields the ball. She is 24 feet from second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball? Round your answer to the nearest tenth.%0D%0A%0D%0A(1 point)%0D%0A feet

Answer 1

To solve this problem, we need to calculate the distance from second base to first base. From the image, we can see that both first base and second base are located at the corners of a square field.

Since the field is square, the distance between second base and home plate is equal to the distance between first base and home plate. Therefore, to find the distance between second base and first base, we can use the Pythagorean theorem.

Let's call the distance from second base to first base "x".

Using the Pythagorean theorem, we have:

x^2 = 24^2 + 90^2

x^2 = 576 + 8100

x^2 = 8676

x ≈ √8676

x ≈ 93.1

Therefore, Haley needs to throw the ball approximately 93.1 feet to first base. Rounded to the nearest tenth, the answer is 93.1 feet.

Answer 2

are you sure ?

Answer 3

Apologies for the mistake in my previous response. Let's recalculate the distance.

To find the distance from second base to first base, we can use the Pythagorean theorem.

Let's call the distance from second base to first base "x".

Using the Pythagorean theorem, we have:

x^2 = 24^2 + 90^2

x^2 = 576 + 8100

x^2 = 8676

x ≈ √8676

x ≈ 93.1

Therefore, Haley needs to throw the ball approximately 93.1 feet to first base. Rounded to the nearest tenth, the answer is 93.1 feet.

I apologize for the confusion earlier. The correct answer is indeed 93.1 feet.