Use the image to answer the question.

A shortstop is standing in the base path between second and third base when she fields the ball. She is 30 feet from second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball? Round your answer to the nearest tenth.

(1 point)
feet

1 answer

To find out how far the shortstop needs to throw the ball to first base, we can visualize the transition from her position between second base and third base.

  1. Understand the positions: In a baseball field, bases are arranged as a square with each side measuring 90 feet. Therefore, the distance from:

    • Second base to third base (along the baseline) is 90 feet.
    • Second base to first base (across the diamond) can be calculated using the Pythagorean theorem, as these two bases form a right triangle.
  2. Identify distances:

    • The shortstop is 30 feet from second base. This means she is 60 feet from third base along the baseline (since the distance from second base to third base is 90 feet).
  3. Find her effective distance:

    • The shortstop is effectively standing at the coordinates of 30 feet from second base (in the direction towards third) and needs to throw to first base which can be visualized as a horizontal throw from her position.
  4. Using the Pythagorean theorem:

    • Set the coordinates:
      • Second base: (0, 0)
      • Third base: (0, 90)
      • First base: (90, 0)
      • Shortstop's coordinates after 30 feet: (0, 30)
    • Calculate the distance to first base:

    \[ d = \sqrt{(90 - 0)^2 + (0 - 30)^2} = \sqrt{90^2 + (-30)^2} = \sqrt{8100 + 900} = \sqrt{9000} \]

  5. Calculate: \[ \sqrt{9000} = 30 \sqrt{10} \approx 30 \times 3.1623 \approx 94.9 \]

  6. Final distance: Thus, rounding to the nearest tenth, the distance the shortstop needs to throw the ball is:

\[ \boxed{94.9} \text{ feet} \]