To find the x-intercepts of the graph of f(x), we need to determine the values of x when f(x) equals zero.
Setting f(x) equal to zero, we have:
2x^2 - 5x + 3 = 0
We can now attempt to factor this quadratic equation. However, it is not easily factorable, so we can instead use the quadratic formula.
The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found by using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
For our equation, a = 2, b = -5, and c = 3. Substituting these values into the quadratic formula, we have:
x = (-(-5) ± √((-5)^2 - 4(2)(3))) / (2(2))
= (5 ± √(25 - 24)) / 4
= (5 ± √1) / 4
Therefore, we have two possible solutions for x:
1) When we take the positive square root:
x = (5 + 1) / 4
= 6 / 4
= 3/2
2) When we take the negative square root:
x = (5 - 1) / 4
= 4 / 4
= 1
So, the x-intercepts of the graph of f(x) are x = 3/2 and x = 1.
Use the function f(x) to answer the questions:
f(x) = 2x2 - 5x+3
Part A: What are the x-intercepts of the graph of f(x)? Show your work.
1 answer