To find the values of the function \( f(x) = 2x^3 - 3x^2 + 7 \) at different points, we can substitute \( x \) with the given values and evaluate the expression.
1. For \( f(-1) \):
\[ f(-1) = 2(-1)^3 - 3(-1)^2 + 7 \]
\[ f(-1) = 2(-1) - 3(1) + 7 \]
\[ f(-1) = -2 - 3 + 7 \]
\[ f(-1) = 2 \]
2. For \( f(1) \):
\[ f(1) = 2(1)^3 - 3(1)^2 + 7 \]
\[ f(1) = 2(1) - 3(1) + 7 \]
\[ f(1) = 2 - 3 + 7 \]
\[ f(1) = 6 \]
3. For \( f(2) \):
\[ f(2) = 2(2)^3 - 3(2)^2 + 7 \]
\[ f(2) = 2(8) - 3(4) + 7 \]
\[ f(2) = 16 - 12 + 7 \]
\[ f(2) = 11 \]
So, the evaluated values are:
\[ f(-1) = 2 \]
\[ f(1) = 6 \]
\[ f(2) = 11 \]
Use the function f(x) = 2x3 - 3x2 + 7 to complete the exercises.
f(−1) =
f(1) =
f(2) =
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