Use the four-step process to find the slope of the tangent line to the graph of the function at the given point and determine an equation of the tangent line.f(x)= x^2 - 5x +2 (1, -2)

Answer 1

f'(x) = 2x-5
f'(1) = -3

So, the line with slope -3 through (1,-2) is

y+2 = -3(x-1)

Not sure what your four-step process is.

Answer 2

So I can just use the point-slope formula to solve equations like this?