slope=6-10x at x=-2
slope=6+20=26
that is pretty steep.
y=mx+b
-32=26*-2 + b
solve for b, and you have the tangent line equation.
y=26x+20 check the math , I did it in my head.
Find the slope m of the tangent line to the graph of the function at the given point and determine an equation of the tangent line.
f(x)=6x-5x^2 at (-2, -32)
I have to use the four step process, but seem to be getting stuck...
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