Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability of the Z score at the ordinate.
Z = (score-mean)/SEm
SEm = SD/√n
Use same table.
Use the following information to answer the following questions. IQ is measured with scores that range from 0-200. Thea mean is 100 and the standard deviation in the population is 15.
What is the probability that a randomly chosen person has an IQ of 115?
Suppose you have a SRS of 9. What is the probability that the sample will have an average IQ of 115?
1 answer
2 answers