To find the efficiency of energy transfer between the harbor seal and the polar bear using the given formula, we can substitute the values into the formula as follows:
\[ \text{Efficiency} = \left( \frac{\text{Energy level transferred to next level}}{\text{Total energy input}} \right) \times 100 \]
Where:
- Energy level transferred to the polar bear = 375 Kcal (energy the polar bear receives from the harbor seal)
- Total energy available from the harbor seal = 2500 Kcal
Now, plug in the values:
\[ \text{Efficiency} = \left( \frac{375 \text{ Kcal}}{2500 \text{ Kcal}} \right) \times 100 \]
Calculating this:
\[ \text{Efficiency} = \left( \frac{375}{2500} \right) \times 100 = 0.15 \times 100 = 15% \]
Therefore, the efficiency of energy transfer between the harbor seal and the polar bear is 15%.
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