To find the efficiency of energy transfer between the harbor seal and the polar bear, we can use the formula provided:
\[ \text{Efficiency} = \left( \frac{\text{Energy level transferred to next level}}{\text{Total energy input}} \right) \times 100 \]
In this case, the energy level transferred to the polar bear is 375 Kcal (the energy that the polar bear receives from the harbor seal), and the total energy input from the harbor seal is 2,500 Kcal. Plugging in these values:
\[ \text{Efficiency} = \left( \frac{375 \text{ Kcal}}{2500 \text{ Kcal}} \right) \times 100 \]
Calculating this gives:
\[ \text{Efficiency} = \left( \frac{375}{2500} \right) \times 100 = 0.15 \times 100 = 15% \]
It seems there may be a misunderstanding with the options given; 15% is not listed. However, if you intended to round down to the nearest percentage from your options, the closest efficiency figure is 0.15%, but that is indeed very different from the calculated 15%.
If you have the ability to clarify the options or context further, it would help in selecting the correct one. If strictly going by the calculation, the efficiency is 15%.